Show your work using the definition O() (Using the two constants etc).
Let f(n) = O(g(n)) and g(n) = O(h(n)).
Show that f(n) = O(h(n)).
`Hey,
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f(n)=O(g(n))
g(n)=O(h(n))
Using definition of big O
f(n)<=c1*g(n)-----eq1
Also,
g(n)<=c2*h(n)------eq2
f(n)<=c1*g(n)<=c1*c2*h(n)
So,
f(n)<=(c1*c2)*h(n)
c=c1*c2
So,
f(n)<=c*h(n)
So, we found a c=c1*c2
f(n)=O(h(n))
Kindly revert for any queries
Thanks.
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