Question

A charge q = -3.75 nC moves with a velocity of 2.75 103 m/s î. Find...

A charge q = -3.75 nC moves with a velocity of 2.75 103 m/s î. Find the force on the charge due to the following magnetic fields. (a) vector B = 0.38 T ĵ 0 Correct: Your answer is correct. µN î + 0 Correct: Your answer is correct. µN ĵ + -3.91 Correct: Your answer is correct. µN k (b) vector B = 0.75 T î + 0.75 T ĵ 0 Correct: Your answer is correct. µN î + 0 Correct: Your answer is correct. µN ĵ + -7.5 Incorrect: Your answer is incorrect. µNk (c) vector B = 0.65 T î 0 Correct: Your answer is correct. µN î + 0 Correct: Your answer is correct. µN ĵ + 0 Correct: Your answer is correct. µN k (d) vector B = 0.75 T î + 0.75 T k 0 Correct: Your answer is correct. µN î + 7.5 Incorrect: Your answer is incorrect. µN ĵ + 0 Correct: Your answer is correct. µN k

0 0
Add a comment Improve this question Transcribed image text
Answer #1

b] Magnetic Force on a charge F = q v x B = -3.75e-9*(2.75e3i^) x (0.75 î + 0.75 ĵ )

= -3.75e-9*2.75e3*0.75 k^

= -0.000007734 N k^

= -7.734 uN k^

d] Magnetic Force on a charge F = q v x B = -3.75e-9*(2.75e3i^) x (0.75 î + 0.75 k^)

= 3.75e-9*2.75e3*0.75 j^

= 0.000007734 N j^

= 7.734 uN j^

Add a comment
Know the answer?
Add Answer to:
A charge q = -3.75 nC moves with a velocity of 2.75 103 m/s î. Find...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A particle with positive charge q = 1.12 10-18 C moves with a velocity v with...

    A particle with positive charge q = 1.12 10-18 C moves with a velocity v with arrow = (5î + 2ĵ − k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle, taking B with arrow = (5î + 2ĵ + k) T and E with arrow = (2î − ĵ − 4k) V/m. (b) What angle does the force vector make with the...

  • 1)A particle of charge = +9 nC and mass = 5 micro-gram) moves with a velocity...

    1)A particle of charge = +9 nC and mass = 5 micro-gram) moves with a velocity V = 3.1 i km/s in a region where the magnetic field is B = 8.9 i + 7.1 j mT. What is the magnitude of the force on the particle due to the magnetic field? Write your answer in nano-newtons. 2)A particle of charge = +1.1 nC and mass = 9 micro-gram) moves with a velocity V = 2.4 i km/s in a...

  • Review Constants A charge of -2.75 nC is placed at the origin of an zy-coordinate system,...

    Review Constants A charge of -2.75 nC is placed at the origin of an zy-coordinate system, and a charge of 1.55 nC is placed on they axis at y = 4.40 cm Express your answer in newtons. F = 8.15x10-5 N Submit Previous Answers Correct Part Find the direction of this force Express your answer in degrees. IVO AED ? 0 = 19.4 clockwise from the axis Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Provide...

  • A particle with positive charge q = 4.01 10-18 C moves with a velocity v =...

    A particle with positive charge q = 4.01 10-18 C moves with a velocity v = (5î + 5ĵ − ) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle, taking B = (5î + 2ĵ + ) T and E = (3î − ĵ − 2) V/m. (Give your answers in N for each component.) Fx= NFy= NFz= N (b) What angle does...

  • D A T 0 05 C charge moves with a velocity of 1000 m/'s to the...

    D A T 0 05 C charge moves with a velocity of 1000 m/'s to the right, and encounters a constant magnetic field of 0,001 pointed 30 degrees from the vertical direction a. What is the direction of the force (show a picture illustrating the vector cross product) b. What is the magnitude of the force? c. If the mass is 1 g, what is the acceleration? d. As the mass continues to move, will the direction of the force...

  • A particle with a charge of q = -5.60 nC is moving in a uniform magnetic...

    A particle with a charge of q = -5.60 nC is moving in a uniform magnetic field of B⃗ =( -1.23 T ) k^. The magnetic force on the particle is measured to be F⃗ =( −7.60×10−7 N )j^. Part B Calculate vx, the x component of the velocity of the particle. Express your answer in meters per second. m/s

  • A particle with a charge of q = -5.20 nC is moving in a uniform magnetic...

    A particle with a charge of q = -5.20 nC is moving in a uniform magnetic field of B with sole component B, = -1.28 T. The magnetic force on the particle is measured to be F with sole component Fy = -7.60x10-7 N Calculate Vz, the x component of the velocity of the particle. Express your answer in meters per second. View Available Hint(s) ΡπΙ ΑΣφ ? v_v_x = 144.2 m/s Submit Previous Answers X Incorrect; Try Again; 3...

  • 5.A particle of charge +2.00 x 103 C is moving with velocity v (1000 m/s)j through...

    5.A particle of charge +2.00 x 103 C is moving with velocity v (1000 m/s)j through a uniform magnetic field. The magnetic force on the particle is F = (4.00 N)i-(6.00 N)k. What is B, the z component of the magnetic field (in T)? (A) 1.00 (B) 1.50 (C) 4.00 (D) 2.00 (E) 3.00 (F) 5.00

  • A charged particle of mass m and positive charge q moves in uniform electric and magnetic...

    A charged particle of mass m and positive charge q moves in uniform electric and magnetic fields, E pointing in the y direction and B in the z direction. suppose the particle is initially at the origin and is given a kick at time t=0 along the x axis with vx = vxo (positive or negative). a) Write down the equation of motion for the particle and resolve it into its three components. show that the motion remains in the...

  • A proton moves along the x-axis with v_x = 1.0 times 10^7 m/s. As it passes...

    A proton moves along the x-axis with v_x = 1.0 times 10^7 m/s. As it passes the origin, what are the strength and direction of the magnetic field at the (1 cm, 0 cm, 0 cm) position? Give your answer using unit vectors. Express your answer in terms of the unit vectors i, j, and k. Use the 'unit vector' button to denote unit vectors in your answer. B = T As it passes the origin, what are the strength...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT