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The heat released by the burning of 0.100 mole of H2 (g) in excess oxygen to...

The heat released by the burning of 0.100 mole of H2 (g) in excess oxygen to give H2O(ℓ) is used to heat an 80.0 g aluminum beaker which contains 100 g of water. If the temperature rise of the beaker and water is 58.3 °C, what is the specific heat, in J K-1 g-1, of aluminum?

  • A.

    1.8

  • B.

    72

  • C.

    0.90

  • D. 4.2

  • E.

    491

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Answer #1

We know that heat of combustion = 286kj/mol

Heat produced by 0.1 mol of hydrogen= 28.6 KJ = 28600j

Heat absorbed by water and aluminium = heat produced by combustion= 28600joule

100×4.18×58.3 +(80× Cal× 58.3)=28600

24369.4+4664× Cal= 28600

4664Cal= 4230.6

Cal= 0.907

Hence option C is the right answer

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