Question

Create the balanced equation for the synthesis of tris(acetylacetonato)aluminum(III). Use the full formulas for the reactants employed in the lab. Explain why all of your syntheses were carried out under alkaline conditions.

I'm not sure what to use, this is what the experiment said: Prepare a solution of 29.2 mmol acetylacetone in 40 mL water and 8 mL of 5M aqueous ammonia. Dissolve 4.87 mmol Al2(SO4)3 · 18 H2O in 30 mL water. With magnetic stirring, slowly add the acac solution to the aluminum solution. Explanation of steps greatly appreciated!

Answer 1

A solution of alum Al2(SO4)3.16H2O (0.1M) was prepared using distilled water. The solution was acidic. To this
solution, an ammoniacal solution of acetylacetone was added in small proportions with continuous stirring and then solution became neutral or slightly basic. Magnetic stirrer is used for 15 minutes . The pale yellow precipitate formed, was filtered, washed with dried under vacuum. Then recrystallised it.