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The Ksp of PbCl2 is 1.7 x 10-5 at 25 C. What is concentration of Cl-...

The Ksp of PbCl2 is 1.7 x 10-5 at 25 C. What is concentration of Cl- in saturated solution of PbCl2?

Answer is 3.2 x 10-2

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Answer #1

Consider dissolution of PbCl 2 in water as PbCl 2(s) Pb 2+(aq) + 2 Cl -(aq)

The solubility product constant for above reaction is

K sp = [Pb 2+ ] [ Cl - ] 2 = 1.7 x 10 -05  

If S is the solubility of PbCl 2 in mol / L , then [Pb 2+ ] = [ PbCl 2 ] = S and   [ Cl - ] = 2 x [ PbCl 2 ] = 2 S.

Therefore, K sp = S x ( 2 S) 2 = 1.7 x 10 -05  

4 S 3 = 1.7 x 10 -05

S 3 = 1.7 x 10 -05  / 4

= 4.25 x 10 -06   

S = 0.0162 mol / L

We have [ Cl - ] = 2 S = 2 x 0.0162 mol / L =3.2 x 10 -02 mol / L

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