A block of mass 2 kg attached to a spring lies on a flat surface. When the block is pulled 5 cm to the right a force with a magnitude of 290 N is need to hold it in place. What is the work done by the spring when the block moves from x = 6 cm to x = 12 cm. Express your answer in joules.
Force, F = kx
Spring constant, k = F/x = 290/0.05 = 5800 N/m
Work, W = 0.5 x 5800 (0.12^2 - 0.06^2) = 31.32 J
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