Question

What is the output of the following?

int x = 50, y = 60, z = 70;

int* ptr;

ptr = &x;

*ptr += 10;

ptr = &y;

*ptr += 5;

ptr = &z;

*ptr -= 3;

cout << x << “ ” << y << “ ” << z << endl;

A) 10 5 2

B) 50 60 70

C) 60 65 67

D) 60 65 72

Answer 1

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Answer 1) :-

Correct option is C. Which is 60 65 67. Because :-

//variable declaration
int x = 50, y = 60, z = 70;
//initialization of pointer ptr
int* ptr;
// A pointer variable that holds address of variable x
ptr = &x;
// Value at address is now incremented by 10 i.e. now x = 60
*ptr += 10;
// A pointer variable that holds address of variable y
ptr = &y;
// Value at address is now incremented by 5 i.e. now y = 65
*ptr += 5;
// A pointer variable that holds address of variable z
ptr = &z;
// Value at address is now decremented by 3 i.e. now z = 67
*ptr -= 3;
//print values of x, y, z separated by space i.e. 60 65 67
cout<<x<<" "<<y<<" "<<z<<endl;

Option A is incorrect as values of x, y, z are incorrect.

Option B is incorrect as values of x, y, z are incorrect.

Option D is incorrect as values of z is incorrect.