dy/dx = y-x/x-y ydx + 2(x+y) =0 y' + 2xy = x^3 (x+y)dx + xdy =0

Question

Question

dy/dx = y-x/x-y

ydx + 2(x+y) =0

y' + 2xy = x^3

(x+y)dx + xdy =0

engineering Electrical-Engineering

Answer 1

Answer #1

Answer 2

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