In rabbits, the English type of coat which is white-spotted (W) and is dominant over the Non-English, unspotted (w) coat while short hair (S) is dominant over long Angora hair (s). When homozygous English, Angoras were crossed with non-English short-haired rabbits, and the F1 dihybrids were test crossed, the following offspring were obtained: 12 English and short-haired rabbits; 10 non-English Angoras; 75 English Angoras and 60 non-English short-haired rabbits. Show progeny phenotype, genotype and totals for each (2pt), calculate the recombination frequency (2pt) and determine the allele configuration (1pt).
I am only stuck on the genotype of the non-English short-haired rabbits
White spots = Dominant = W
Unspotted = Recessive = w
Short hair = Dominant = S
Long hair = Recessive = s
Parental cross: WWss X wwSS
F1 progeny: WwSs
F1 test cross: WwSs X wwss
Progeny:
Parental combinations:
Ws/ws = White spots and long hair = 75
wS/ws = Unspotted and short hair = 60
Recombinants:
WS/ws = White spots and short hair = 12
ws/ws = Unspotted and long hair = 10
If genes are unlinked, all the phenotypic classes would appear in equal proportions i.e. 1:1:1:1
Recombination frequency = (Number of
recombinants/Total progeny) X 100
= [(12+10)/(12+10+75+60)] X 100
= 14.01 mu
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