Question

A current of 3.18 A is passed through a Sn ( NO 3 ) 2 solution for 1.20 h . How much tin is plated out of the solution??

Answer 1

Answer:

•   Equivalent mass of Sn = 118.7/2
• = 59.35 g
• Q = it
• = 3.68*t
• Therefore
• No. of Equivalent Deposit = (3.18*1.2)*60*60/96500
• i/59.35 = (3.18*1.2)*60*60/96500
• m = 59.35*(3.18*1.2)*60*60/96500
• = 8.448gm

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