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3. Write a function that makes the following calculation: param1 * param2 / param3 * param4...

3. Write a function that makes the following calculation: param1 * param2 / param3 * param4 / param5...and keeps with this pattern. If any non-numerical character is encountered, 1⁄4 of its value is computed as the numerical value. The result should truncate precision. E.G. function(11,’a’,2,30,’z’,3) returns 393 11 * (97/4) / 2 * 30 / (122/4) * 3

Also no built in functions allowed

DONT USE THIS FUNCTION PLEASE: function expression(param1, param2, param3, param4, param5) { if (param1 !== parseInt(param1)) param1 = param1.charCodeAt(0) / 4; if (param2 !== parseInt(param2)) param2 = param2.charCodeAt(0) / 4; if (param3 !== parseInt(param3)) param3 = param3.charCodeAt(0) / 4; if (param4 !== parseInt(param4)) param4 = param4.charCodeAt(0) / 4; if (param5 !== parseInt(param5)) param5 = param5.charCodeAt(0) / 4; return Math.floor(param1 * param2 / param3 * param4 / param5); }

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Homework Answers

Answer #1

Code:

import math

def function(arr):

ans = int(arr[0])

for index in range(1,len(arr)):

if type(arr[index]) is int:

x = arr[index]

else:

x = ord(arr[index])

if index%2 == 1:

ans = ans * x

else:

ans = ans / x

return math.floor(ans)

def main():

ans = function([11,"a",2,30,"z",3])

print(ans)

main()

Output:

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