If 19.6 grams of an aqueous solution of
ammonium bromide,
NH4Br, contains 1.92
grams of ammonium bromide, what is the percentage
by mass of ammonium bromide in the
solution?
Percentage by mass of ammonium bromide = 9.80 %
Explanation
mass of solution = 19.6 g
mass NH4Br in solution = 1.92 g
% (by mass) NH4Br in solution = (mass NH4Br in solution / mass of solution) * 100
% (by mass) NH4Br in solution = (1.92 g / 19.6 g) * 100
% (by mass) NH4Br in solution = (0.0980) * 100
% (by mass) NH4Br in solution = 9.80 %
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