Question

create a c language program that utilizes a static variable to calculate the zeroes of a quadratic equation.

Answer 1

CODE:

#include <stdio.h>
#include <math.h>
int main()
{
   //Zeros of the equation: points at which given curve touches the x-axis are called zeros of that equation.
static int a, b, c, discriminant; //declaring static variable which represents coefficients of equation
static double root1, root2; //declaring static double root variables
printf("Enter a, b and c in a*x^2 + b*x + c = 0:\n");
scanf("%d%d%d", &a, &b, &c); //input the coefficients

discriminant = b*b - 4*a*c; //calculating the descriminent
printf("Zeros of the exuation %dx^2+%dx+%d=0 are:\n",a,b,c);
if (discriminant < 0) { //deciding roots based on descriminent
printf("(%.2lf + i%.2lf,0)\n", -b/(double)(2*a), sqrt(-discriminant)/(2*a)); //calculating the zeros of equation
printf("(%.2lf - i%.2lf,0)", -b/(double)(2*a), sqrt(-discriminant)/(2*a));
}
else { //here roots are real numbers
root1 = (-b + sqrt(discriminant))/(2*a); //calculating the zores of the equation
root2 = (-b - sqrt(discriminant))/(2*a);

printf("(%.2lf,0)\n", root1);
printf("(%.2lf,0)", root2);
}

return 0;
}

OUTPUT: