Suppose 36% of movie-goers say that horror is their favorite movie genre. If a random
sample of 120 movie-goers is taken, what are the mean and standard deviation of the
number of movie-goers that prefer horror?
Solution :
Given that,
p = 36%=0.36
q = 1 - p =1-0.36=0.64
n = 120
Using binomial distribution,
mean =
= n * p = 120*0.36=43.2
standard deviation
=
n * p * q =
120*0.36*0.64=5.2581
Suppose 36% of movie-goers say that horror is their favorite movie genre. If a random sample...
Suppose 36% of movie-goers say that horror is their favorite movie genre. If a random sample of 120 movie-goers is taken, what are the mean and standard deviation of the number of movie-goers that prefer horror? A. mu equals 0.36 comma sigma equals 0.0438μ = 0.36, σ = 0.0438 B. mu equals 0.36 comma sigma equals 0.0019μ = 0.36, σ = 0.0019 C. mu equals 43.2 comma sigma equals 27.648μ = 43.2, σ = 27.648 D. mu equals 43.2 comma...
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A group of movie executives is interested in gender differences in movie genre preferences. They take a random sample of self-reported males and females and finds that 17 of the females report that comedy is their favorite type of movie whereas 20 report drama as their favorite, 13 choose thrillers as their favorite, and 10 choose documentaries. Among males, 18 choose comedies, 11 choose dramas, 21 choose thrillers, and 7 choose documentaries as their favorites. 1. Develop a bivariate table...
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