Let X be a binomial random variable with n = 100 and p = 0.2. Find...

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Let X be a binomial random variable with n = 100 and p = 0.2. Find...

Let X be a binomial random variable with n = 100 and p = 0.2. Find approximations to these probabilities. (Round your answers to four decimal places.) (c) P(22 < X < 26)

math Statistics-And-Probability

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Answer 1

Answer #1

here mean of distribution=μ=np=

20.00

and standard deviation σ=sqrt(np(1-p))=

4.00

for normal distribution z score =(X-μ)/σx

therefore from normal approximation of binomial distribution and continuity correction:

probability =P(22.5<X<25.5)=P((22.5-20)/4)<Z<(25.5-20)/4)=P(0.63<Z<1.38)=0.9162-0.7357=0.1805

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Answer 2

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Let X be a binomial random variable with n = 100 and p = 0.2. Find...

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