Question

A hawk is flying horizontally Southward at an altitude of 187.0 m and at a speed of 2.20 m/s when he spots a slow-flying finch ahead of his current location and below his current path. At time zero, the hawk starts a dive by controlling the contact forces on him by the air so as to produce an acceleration of 4.00 m/s2 in a direction 80.0 degrees below horizontally Southward for a time of 0.750 seconds.

Part A

What is the hawk's final velocity at the end of the 0.750-s interval?

Part B

What is the hawk's displacement during the 0.750-s interval? (additional info Starting at the end of the 0.750-s interval, the hawk dives at a constant velocity for 6.5 s.)

Part C What is the hawk's displacement during the 6.5-s interval? (additional info At the end of the 6.5-s interval, the hawk misses the finch and has to "put on the brakes". He does so by controlling the contact forces on him by the air so as to produce an acceleration of 0.785 m/s2 in a direction 66.522 degrees above horizontally Northward for a time of 1.5 seconds.)

Part D

Once again, please assume that the hawk's acceleration during the 1.5-s interval is constant. What is the hawk's displacement during the 1.5-s interval? (additional info You have now been tracking the hawk's motion for a total of 0.750 + 6.5 + 1.5 = 8.75 seconds.)

Answer 1