A marketing study was conducted to compare the mean age of male and female purchasers of a certain product. Random and independent samples were selected for both male and female purchasers of the product. It was desired to test to determine if the mean age of all female purchasers exceeds the mean age of all male purchasers. The sample data is shown here:
Female: n = 10, sample mean = 50.30, sample standard deviation = 13.215
Male: n = 10, sample mean = 39.80, sample standard deviation = 10.040
Which of the following assumptions must be true in order for pooled test of hypothesis to be valid?
i. Both the male and female populations of ages must possess approximately normal probability distributions.
ii. Both the male and female populations of ages must possess population variances that are equal.
iii. Both samples of ages must have been randomly and independently selected from their respective populations.
A) i, ii, and iii
B) i only
C) iii only
D) ii only
Ans:
Option A is correct.
i,ii, and iii
For using,indpendent samples t test(pooled),samples must be selected randomly and indpendently from the normally distributed populations.
A marketing study was conducted to compare the mean age of male and female purchasers of...
Question 18 4 pts A marketing study was conducted to compare the mean age of male and female purchasers of a certain product. Random and independent samples were selected for both male and female purchasers of the product. What type of analysis should be used to compare the mean age of male and female purchasers? A test of a single population mean. An independent samples comparison of population proportions. An independent samples comparison of population means. O Apaired difference comparison...
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A study to compare the means of the age x at first marriage of
men and women obtained the information shown, where the men and
women were sampled independently of one another. We may assume that
the populations of ages are normally distributed with approximately
equal standard deviations.
n
x
¯
s
male
50
26.8
0.21
female
50
25.1
0.19
The correct formula to employ to use these data to construct a
90% confidence interval for the difference in mean...
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