A 220-V, 1.5-hp, 50-Hz, six-pole, capacitor-start induction
motor has the following
main-winding impedances:
R1= 1.30 Ω R2 = 1.73 Ω Xl = 2.01 Ω X2 = 2.01 Ω Xm = 105 Ω At a slip
of 0.05, the motor's rotational losses are 291 W. The rotational
losses may be
assumed constant over the nominal operating range of the motor.
Find the following
quantities for this motor at 5 percent slip:
(e) Tin
(f) Find the induced torque if it is operating at 5 percent slip
and its terminal voltage is 190 V
(g)calculate the starting torque at this case.
A 220-V, 1.5-hp, 50-Hz, six-pole, capacitor-start induction motor has the following main-winding impedances: R1= 1.30 Ω...
A 220-V, 1.5-hp, 50-Hz, six-pole, capacitor-start induction motor has the following main-winding impedances: R1= 1.30 Ω R2 = 1.73 Ω Xl = 2.01 Ω X2 = 2.01 Ω Xm = 105 Ω At a slip of 0.05, the motor's rotational losses are 291 W. The rotational losses may be assumed constant over the nominal operating range of the motor. Find the following quantities for this motor at 5 percent slip: (a) Stator current (b) Stator power factor (e) Input power...
Problem 2. (25 points) For a 120-V, 1/3 hp, four pole, 1-phase induction motor, the parameters of the equivalent circuit, are R,-1.8(2, R,-2.5Ω, X,-X,-2.462, and Xm-60 Ω. At a slip of 500, the motor's rotational losses are 51W. The rotational losses maybe assumed constant over the normal operating range of the motor. If the slip is 0.05, calculate a. Input Power b. Air Gap Power, c. Induced Torque Tin d. Output power e. Load torque. f. Overall Motor efficiency g....
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per phase referred to the stator circuit. Ri= 0.212 R2 = 0.282 X1 = 1.055 12 X2 = 1.055 22 XM = 33.9 W The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped with the rotational losses. For a rotor slip of 4% at the rated voltage and rated frequency, a) The input power b) Peony...
A 3-phase, 208 V, 60 Hz, 30 hp, four-pole induction motor has the following equivalent circuit parameters. R1 = 0.2 Ω, , , Xm = 12Ω.The rotational loss is 500 W. For a slip of 5%, calculate (a) The motor speed in rpm and radians per sec (b) The current drawn by the motor from the power supply (c) The stator cu-loss (d) The air gap power (e) The rotor cu-loss (f) The shaft power (g)The developed torque and the shaft torque (h) The efficiency of the motor Use...
A three-phase 4 pole wye connected 220 V, 15 Hp, 50 Hz induction machine (rated conditions) has the following parameters per phase refereed to the stator. RI : 0.29 Ω , R2 0. 14 Ω , Xi-0.50 Ω , X2-0.20 Ω , Xm-1 0.53 Ω The total windage and core losses can be assumed to be a constant 350 W. If the machine is operating at rated voltage and frequency with a 5.5% slip, find the steady-state: (a) 10pts. Mechanical...
A 480 V, 60 Hz, 4-pole-pair, three-phase, delta-connected induction motor has the following parameters: R1=0.42 Ω, R2=0.23 Ω, X1=0.48 Ω, X2=0.29 Ω, Xm=29.71 Ω where: R1 is the stator resistance R2 is the rotor resistance reflected in the stator; X1 is the stator leakage inductance; X2 is the rotor leakage inductance reflected in the stator; Xm is the magnetising inductance; The rotational losses are 2450 W. The motor drives a mechanical load at a speed of...
Please solve this question. Thank you.
A two-pole, 75kW, 440 V, 50 Hz, Y-connected, three-phase squirrel cage induction motor has the following parameters, in Ω/phase referred to the stator: R1-0.075, XI 0.17, xm-72, R2-0.065 and X-0.17. Its rated slip is 4%. Assume that the mechanical losses are 1 kW and the core losses are 1.1 kW. Compute: a. The rated input current b. The rated power factor. c. The pullout torque d. The induced and load torques at rated conditions....
A 230 V, 50 Hz, three-phase, Y-connected, 6-pole induction motor has the following per-phase parameters R-0.07 Ro 00 0.08 Ω x, x, 0.3 xm 6.33 At a slip of 2%, determine the followings using approximate equivalent circuit of the motor i) The motor speed in rev/min and rad/s. ii) The rotor current. ii) The stator current. iv) The induced torque. v) The efficiency of the motor.
4. A 50-kW, 460-V, 50-Hz, two-pole induction motor has a slip of 5 percent when operating a full-load conditions. At full-load conditions, the friction and windage losses are 700 W, and the core losses are 600 W. Find the following values for full-load conditions: (10 pts.) (a) The shaft speed in rpm (b) The output power in horse power (c) The load torque in lb-ft (d) The induced torque in lb-ft (e) The rotor frequency in hertz
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