1. Recall that gravity is the force that provides the centripetal acceleration to keep the planets...
1. Recall that gravity is the force that provides the centripetal acceleration to keep the planets in elliptical
orbits around the sun. For this problem, approximate Earth’s orbit as a circle, as we have done in class.
(a) What is the angular velocity of Earth while it orbits the sun?
(b) If Earth were twice as close to the sun as it is now, what would its new angular velocity be?
(c) With this angular velocity, how long would a year be?
Homework Answers
Concept - equate the gravitational force to centripetal force to find the angular velocity as shown below. Find the new angular velocity using the new radius. Use the new angular speed to find the time period which gives the duration of a year.
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1. Recall that gravity is the force that provides the
centripetal acceleration to keep the planets...
QUESTION 2 Remember that centripetal force and centripetal acceleration is the special name we give to...
QUESTION 2 Remember that centripetal force and centripetal acceleration is the special name we give to the inwards force and acceleration that causes (forces) the object to move in a circle In the case of gravity where gravity causes a planet or satelite or star to orbit around another larger body, then gravity force is the centripetal force Centripetal force is the net force, and centripetal acceleration is the net acceleration. What is the centripetal acceler ation of a planet...
01. (i) Calculate the centripetal acceleration of the Earth in its orbit around the Sun, (ii)...
01. (i) Calculate the centripetal acceleration of the Earth in its orbit around the Sun, (ii) And the net force exerted on the Earth. iii) What exerts this force on the Earth? Assume that the Earth's orbit is a circle of radius 1.5 X 10' m (iv) Calculate the Gravitational Force between the Earth and the Sun. (v) Compare the Gravitational Force to that net force from section (ii) above. Given that F mg (vi) Calculate the acceleration due to...
Which of the following would count as a centripetal force? (Choose All That Apply) The force...
Which of the following would count as a centripetal force? (Choose All That Apply) The force of gravity causing the earth to travel in a circular path around the sun The tension in a rope as you swing a yo-yo in a circle over your head The force of friction from the seat on you as you travel around a curve while driving a car The normal force acting on a car as it drives in a circle All of...
The moon does not fall to earth because: The moon is beyond the main pull of...
The moon does not fall to earth because: The moon is beyond the main pull of Earth's gravity. The moon is pulled by the sun and planets as well as by Earth. The gravitational force provides the required centripetal force for the moon to have its tangential speed around the Earth. The net force on the moon is zero. The moon is in earth's gravitational field. Question 3 (4 points) The tallest mountain in our solar system is Mt. Caloris...
Does the force of gravity alone provide the means for the centripetal force, is this why...
Does the force of gravity
alone provide the means for the centripetal force, is this why they
are equal ? For explaining why there is no normal force, could you
see it as the astronaut having the same acceleration as the ship
and so the relative acceleration = 0, so it's under the illusion
almost of having no acceleration so there's no force ? Please !! If
you have different reasoning please share. I'm just trying to wrap
my head...
All questions please 101. The mass of the Earth is almost 6.0x104 kg, and the average...
All questions please
101. The mass of the Earth is almost 6.0x104 kg, and the average radius is about 6400 km. A satellite with a mass of 70 Kg is orbiting at an altitude of 600 km. Calculate the acceleration with which the satellite is falling on Earth. a. 5.7x10 m/s b. 5.7x10 m/s c. 5.7x10° m's d. 5.7x10 m/ e. 5.7x10m/s 102. The mass of the Earth is almost 6.0x 10* kg, and the average radius is about 6400...
(a) Explain the relationship between the universal gravitational constant G and the acceleration due to gravity...
(a) Explain the relationship between the universal gravitational constant G and the acceleration due to gravity at the earth's surface g. Therefore, calculate g from G using the relationships given below. Justify the choice of units for G (Nm kg?). F= mg The mass of the earth is 5.98 x 1024 kg, it's radius is Tg = 6.38 x 10 m, and G = 6.67 x 10-11 Nm?kg (10 marks) (b) Explain, including performing the integral, how the work done...
Can someone help me with this question and show all work 1) Planet Velocities and Energy...
Can someone help me with this question and show all
work
1) Planet Velocities and Energy (33 pts) We talked about how planet formation involves the collisions of bodies (planetesimals, embryos) leading to the growth (and heating) of a planet. Let's think about the velocities and energies involved here. a) The speed of a body in its orbit around the Sun is given by the equation: Here Vis the speed of the body in m/s, G is the gravitational constant,...
For the purposes of this problem, use the following data: mass of Comet 67P is 1...
For the purposes of this problem, use the following data: mass of Comet 67P is 1 times 10^13 kg; radius of Comet 67P is 2.30 km; mass of Philae = 100 kg; mass of Rosetta = 1000 kg; radius of Rosetta's orbit was 22.3 km (a) What is the acceleration due to gravity on the surface of the comet, where Philae is? m/s^2 (b) What is the escape speed at the surface of the comet? This is the speed above...
On February 7, 1999, NASA launched a spacecraft with the ambitious mission of making a close...
On February 7, 1999, NASA
launched a spacecraft with the ambitious mission of making a close
encounter with a comet, collecting samples from its tail, and
returning the samples to Earth for analysis. This spacecraft,
appropriately named Stardust, took almost five years to
rendezvous with its objective-comet Wild 2 (pronounced "Vilt
2")-and another two years to return its samples. The reason for the
long round trip is that the spacecraft had to make three orbits
around the Sun, and also...
QUESTION 2 Remember that centripetal force and centripetal acceleration is the special name we give to the inwards force and acceleration that causes (forces) the object to move in a circle In the case of gravity where gravity causes a planet or satelite or star to orbit around another larger body, then gravity force is the centripetal force Centripetal force is the net force, and centripetal acceleration is the net acceleration. What is the centripetal acceler ation of a planet...
01. (i) Calculate the centripetal acceleration of the Earth in its orbit around the Sun, (ii) And the net force exerted on the Earth. iii) What exerts this force on the Earth? Assume that the Earth's orbit is a circle of radius 1.5 X 10' m (iv) Calculate the Gravitational Force between the Earth and the Sun. (v) Compare the Gravitational Force to that net force from section (ii) above. Given that F mg (vi) Calculate the acceleration due to...
Which of the following would count as a centripetal force? (Choose All That Apply) The force of gravity causing the earth to travel in a circular path around the sun The tension in a rope as you swing a yo-yo in a circle over your head The force of friction from the seat on you as you travel around a curve while driving a car The normal force acting on a car as it drives in a circle All of...
The moon does not fall to earth because: The moon is beyond the main pull of Earth's gravity. The moon is pulled by the sun and planets as well as by Earth. The gravitational force provides the required centripetal force for the moon to have its tangential speed around the Earth. The net force on the moon is zero. The moon is in earth's gravitational field. Question 3 (4 points) The tallest mountain in our solar system is Mt. Caloris...
Does the force of gravity
alone provide the means for the centripetal force, is this why they
are equal ? For explaining why there is no normal force, could you
see it as the astronaut having the same acceleration as the ship
and so the relative acceleration = 0, so it's under the illusion
almost of having no acceleration so there's no force ? Please !! If
you have different reasoning please share. I'm just trying to wrap
my head...
All questions please
101. The mass of the Earth is almost 6.0x104 kg, and the average radius is about 6400 km. A satellite with a mass of 70 Kg is orbiting at an altitude of 600 km. Calculate the acceleration with which the satellite is falling on Earth. a. 5.7x10 m/s b. 5.7x10 m/s c. 5.7x10° m's d. 5.7x10 m/ e. 5.7x10m/s 102. The mass of the Earth is almost 6.0x 10* kg, and the average radius is about 6400...
(a) Explain the relationship between the universal gravitational constant G and the acceleration due to gravity at the earth's surface g. Therefore, calculate g from G using the relationships given below. Justify the choice of units for G (Nm kg?). F= mg The mass of the earth is 5.98 x 1024 kg, it's radius is Tg = 6.38 x 10 m, and G = 6.67 x 10-11 Nm?kg (10 marks) (b) Explain, including performing the integral, how the work done...
Can someone help me with this question and show all
work
1) Planet Velocities and Energy (33 pts) We talked about how planet formation involves the collisions of bodies (planetesimals, embryos) leading to the growth (and heating) of a planet. Let's think about the velocities and energies involved here. a) The speed of a body in its orbit around the Sun is given by the equation: Here Vis the speed of the body in m/s, G is the gravitational constant,...
For the purposes of this problem, use the following data: mass of Comet 67P is 1 times 10^13 kg; radius of Comet 67P is 2.30 km; mass of Philae = 100 kg; mass of Rosetta = 1000 kg; radius of Rosetta's orbit was 22.3 km (a) What is the acceleration due to gravity on the surface of the comet, where Philae is? m/s^2 (b) What is the escape speed at the surface of the comet? This is the speed above...
On February 7, 1999, NASA
launched a spacecraft with the ambitious mission of making a close
encounter with a comet, collecting samples from its tail, and
returning the samples to Earth for analysis. This spacecraft,
appropriately named Stardust, took almost five years to
rendezvous with its objective-comet Wild 2 (pronounced "Vilt
2")-and another two years to return its samples. The reason for the
long round trip is that the spacecraft had to make three orbits
around the Sun, and also...
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