pea plant homozygous for flower positionAa are allowed to self pollinate and 41 of the resulting...
pea plant homozygous for flower positionAa are allowed to self pollinate and 41 of the resulting seeds are planted . Draw a punnett sqyare for thids cross and determine how many offspring would be produced to have terrestrial flowers knowing that axial flower is dominant over terminal flower. what is the ratio of genptypes in the offspring?
Homework Answers
The allele A encodes axial flower which is dominant over a allele encoding terminal flower.
Please look in the image for solution.
genotypic ratio of offspring in F2 is : AA: Aa : aa
1 : 2 : 1
phenotypic ration is Axial: terminal
3 : 1
Offspring having terminal flower is 1/4 × 41 =10.25 which is equal to 10 when round off.
Offspring having axial flower is 3/4 × 41=30.75 which is equal to 31 when round off.
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