Question

a) Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 112 V.

1.44*10e5 Incorrect: Your answer is incorrect. What is the relationship between electric potential difference and energy? m/s (b) Calculate the speed of an electron that is accelerated through the same potential difference.

6.28*10e6 Incorrect: Your answer is incorrect. This problem can be worked using force and acceleration or by using energy conservation. Which approach is generally easier when both work? m/s

Answer 1

( a ) ΔK = q V ;

0.5 m v^2 = q V ;

0.5 ( 1.67 e -27 ) ( v^2 ) = ( 1.6 e -19 ) 112

=> v = 1550367.93 m /s

( b )

0.5 m v^2 = q V ;

0.5 ( 9.1 e -31 ) v^2 = ( 1.6 e -19 ) 112;

=> v = 66415938.77 m /s