1.
Suppose it is known that 76% of Winnipeggers have been to Grand Beach. In a random sample of 800 Winnipeggers, what is the approximate probability that at least 78% of them have been to Grand Beach?
Question 32 options:
|
0.0734 |
|
|
0.0934 |
|
|
0.1334 |
|
|
0.0534 |
|
|
0.1134 |
2.
The next two questions (2 and 3) refer to the following:
Three of the films nominated for the 2019 Best Picture Academy Award were Roma, Black Panther and A Star Is Born. Suppose we have the following information about movie fans in Canada:
16% of movie fans have seen Roma.
59% of movie fans have seen Black Panther.
83% of movie fans have seen Black Panther or A Star Is Born.
24% of movie fans have seen Black Panther and A Star Is Born.
11% of movie fans have seen Roma and Black Panther.
7% of movie fans have seen Roma and A Star Is Born.
4% of movie fans have seen all three films.
What is the probability that a randomly selected Canadian movie fan has seen A Star Is Born?
Question 27 options:
|
0.44 |
|
|
0.39 |
|
|
0.37 |
|
|
0.41 |
|
|
0.48 |
3.
What is the probability that a randomly selected Canadian movie fan has seen only Roma (and not the other two movies)?
Question 28 options:
|
0.02 |
|
|
0.06 |
|
|
0.05 |
|
|
0.04 |
|
|
0.03 |
1.
Standard error =
= 0.0151
P(p > 0.78) = P[Z > (0.78 - 0.76)/0.0151] = P[Z > 1.32] = 0.0934
2.
P(Black Panther or A Star Is Born) = P(A Star Is Born) + P(Black Panther) - P(Black Panther and A Star Is Born)
0.83 = P(A Star Is Born) + 0.59 - 0.24
P(A Star Is Born) = 0.83 - 0.59 + 0.24 = 0.48
3.
P(only Roma) = P(Roma) - P(Roma and Black Panther) - P(Roma and A Star Is Born) + P(all three films)
= 0.16 - 0.11 - 0.07 + 0.04
= 0.02
1. Suppose it is known that 76% of Winnipeggers have been to Grand Beach. In a...