Question

1. Suppose it is known that 76% of Winnipeggers have been to Grand Beach. In a...

1.

Suppose it is known that 76% of Winnipeggers have been to Grand Beach. In a random sample of 800 Winnipeggers, what is the approximate probability that at least 78% of them have been to Grand Beach?

Question 32 options:

0.0734

0.0934

0.1334

0.0534

0.1134

2.

The next two questions (2 and 3) refer to the following:

Three of the films nominated for the 2019 Best Picture Academy Award were Roma, Black Panther and A Star Is Born. Suppose we have the following information about movie fans in Canada:

  • 16% of movie fans have seen Roma.

  • 59% of movie fans have seen Black Panther.

  • 83% of movie fans have seen Black Panther or A Star Is Born.

  • 24% of movie fans have seen Black Panther and A Star Is Born.

  • 11% of movie fans have seen Roma and Black Panther.

  • 7% of movie fans have seen Roma and A Star Is Born.

  • 4% of movie fans have seen all three films.

What is the probability that a randomly selected Canadian movie fan has seen A Star Is Born?

Question 27 options:

0.44

0.39

0.37

0.41

0.48

3.

What is the probability that a randomly selected Canadian movie fan has seen only Roma (and not the other two movies)?

Question 28 options:

0.02

0.06

0.05

0.04

0.03

0 0
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Answer #1

1.

Standard error = = 0.0151

P(p > 0.78) = P[Z > (0.78 - 0.76)/0.0151] = P[Z > 1.32] = 0.0934

2.

P(Black Panther or A Star Is Born) = P(A Star Is Born) + P(Black Panther) - P(Black Panther and A Star Is Born)

0.83 = P(A Star Is Born) + 0.59 - 0.24

P(A Star Is Born) = 0.83 - 0.59 + 0.24 = 0.48

3.

P(only Roma) = P(Roma) - P(Roma and Black Panther) - P(Roma and A Star Is Born) + P(all three films)

= 0.16 - 0.11 - 0.07 + 0.04

= 0.02

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