The useful life of an electrical component is exponentially distributed with a mean of 5,000 hours.
a. What is the probability the circuit will last more than 5,750 hours?
b. What is the probability the circuit will last between 5,000 and 5,250 hours?
c. What is the probability the circuit will fail within the first 4,750 hours?
X ~ Exp (
)
Where,
Mean = 1 /
= 5000 So,
= 1 / 5000
a)
P( X > x) = e-
X
So,
P( X > 5750) = e-5750 / 5000
= 0.3166
b)
P(x1 < X < x2) = e-x1
-
e-x2
So,
P(5000 < X < 5250) = e-5000/5000 - e-5250/5000
= 0.0179
c)
P( X < x) = 1 - e-
X
So,
P( X < 4750) = 1 - e-4750/5000
= 0.6133
The useful life of an electrical component is exponentially distributed with a mean of 5,000 hours....
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