Question

C++ Code a program to reproduce Mary's clairvoyant test: Mary conjures up a random number 1-10 in her mind and commands the user to guess what it is. If the user’s guess is equal to (remember your double equal sign!) the conjured number, Mary extends a job offer as a clairvoyant assistant. Add a user-driven loop that allows the user to play repeatedly if desired (but your program should conjure a new random number with every loop iteration). Example code: Mary is thinking of a number 1-10...Guess what it is!: 6 Sorry, that is incorrect. Play again? (y/n): y Mary is thinking of a number 1-10...Guess what it is!: 5 That is correct! Mary would like to hire you as a clairvoyant assistant. Play again? (y/n): n Press any key to continue . . .

Answer 1

Solution:

#include<iostream>
using namespace std;
#include<stdio.h>

int main()
{
   char choice='y';
   int random_number,user_guess;

   do
   {
       //rand() generates numbers from 0 to 9 so we add 1 to make the range 1-10
       random_number=rand()%10+1;
       cout<<"Mary is thinking of a number 1-10...Guess what it is!:";
       cin>>user_guess;
       if(random_number==user_guess)
           cout<<"That is correct!";
       else
           cout<<"Sorry, that is incorrect.";
          
       cout<<"\nPlay again? (y/n): ";
       cin>>choice;
   }while(choice!='n');

   return 0;
}

Output: