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A chemist must prepare 850. mL of 510. mM aqueous aluminum chloride AlCl 3 working solution....

A chemist must prepare 850. mL of 510. mM aqueous aluminum chloride AlCl 3 working solution. He'll do this by pouring out some 0.782 mol L aqueous aluminum chloride stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the aluminum chloride stock solution that the chemist should pour out. Round your answer to 3 significant digits.

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Answer #1

Using dilution law

M1V1 = M2V2

0.510×850 = 0.782×V2

V2 = 554. mL

So volume of stock solution should poue out is

554. mL

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