A 10 g inflated balloon falls at a constant velocity. What is the buoyant force acting on the balloon? (Ignore frictional force).
Since the balloon falls with constant velocity, net force on balloon is zero.
So upward buoyant force = downward gravitational force or weight
= mg
= 0.010 kg *9.8 m/s^2
= 0.098 N answer
A 10 g inflated balloon falls at a constant velocity. What is the buoyant force acting...
A balloon inflated with helium
gas (density = 0.2 kg/m3) has a volume of 6 × 10–3 m3. If the
density of air is 1.3 kg/m3, what is the buoyant force exerted on
the balloon?
Test Bank, Question 29 A balloon inflated with helium gas (density = 0.2 kg/m3) has a volume of 6 x 10-3 m3. If the density of air is 1.3 kg/m3, what is the buoyant force exerted on the balloon? o0.01 N o0.08 N О 0.8N...
Consider a helium balloon with volume 2.15 L. a. Calculate the buoyant force on the balloon, in newtons. Use 1.29 kg/m3 for the density of air. b. Given the mass of the rubber in the balloon is 1.65 g, what will be the net force, in newtons, in the vertical direction (taking up as positive) on the balloon if it is released? Neglect the volume of the rubber, and use 0.18×10-3 g/cm3 for the density of helium.
Calculate the buoyant force (in N) on a 2.20 L helium balloon. Given the mass of the rubber in the balloon is 1.10 g, what is the net vertical force (in N) on the balloon if it is let go? You can neglect the volume of the rubber.
Calculate the buoyant force on a 2.70 L helium balloon. N (upward) (b) Given the mass of the rubber in the balloon is 1.00 g, what is the net vertical force on the balloon if it is let go? You can neglect the volume of the rubber. N (upward)
a) Calculate the buoyant force (in N) on a 2.30 L helium balloon. I got .029 N upward for part a but can't seem to figure out part b. b) Given the mass of the rubber in the balloon is 2.00 g, what is the net vertical force (in N) on the balloon if it is let go? You can neglect the volume of the rubber.
A 2.00 g air‑inflated balloon is given an excess negative charge, ?1=−3.50×10−8 C, by rubbing it with a blanket. It is found that a charged rod can be held above the balloon at a distance of ?=5.40 cm to make the balloon float. Assume the balloon and rod to be point charges. The Coulomb force constant is 1/(4??0)=8.99×109 N⋅m2/C2 and the acceleration due to gravity is ?=9.81 m/s2. How much charge ?2 does the rod have?
What would the buoyant force be if its acting on a 25-ton motorboat that is floating in the lake? Explain.
Question7 of 10 A 0.00230 kg air-inflated balloon is given an excess negative charge q1 -3.75 x 10-8 C by rubbing it with a blanket. It is found that a charged rod can be held above the balloon at a distance of d = 0.0540 m to make the balloon float. In order for this to occur, what polarity of charge must the rod possess? O proton O neutral O negative positive How much charge q does the rod have?...
The
buoyant force in the 500 kg balloon is Fb = 6kN and the air exerts
a resistance Fr = (100v) N, where v is given in m / s. Determine
the velocity of the balloon 5s after leaving (taking off) at rest
and ascending.
repuso FR (100U)N
repuso FR (100U)N
QUESTION 10 A 110 kg skydiver falls due the force of gravity. The magnitude of the force of gravity on the Earth due to the skydiver is_ N. QUESTION 11 A student pushes a 60 kg couch across a carpet at a constant velocity. He must overcome a frictional force of 100 N. The magnitude of the force of the student on the couch is N. QUESTION 11 A student pushes a 60 kg couch across a carpet at a...