Question

1a. Gene G is a coding region, and expression of gene G causes a phenotype. Which of the following is accurate about a population in Hardy Weinberg Equilibrium, with respect to gene G? Choose all accurate answers.

	The species cannot be sexually reproducing, because sexual reproduction changes allele frequencies of gene G.
	Inbreeding is not causing a change in the genotype frequencies of gene G.
	Somatic mutations cannot be happening, because somatic mutations change allele frequencies of gene G.
	Gene flow is not happening, with respect to the alleles of gene G.

1b. Consider that a population has a gene with 2 alleles, G and g. The frequency of the G allele is 0.8. The frequency of the g allele is 0.2. This is all that you know.

What is the frequency of the GG genotype?

0.45
	0.16
	It is impossible to determine this from the information provided in the question
	0.64
	0.04
	0.32

I'm leaning towards it is impossible to predict.

Answer 1

1.a.

The species cannot be sexually reproducing, because sexual reproduction changes allele frequencies of gene G.

This is one of the right options because, sexual reproduction brings more variations in the population. Because the gene freqeuncy is not changing, there is a possibility that the organism is reproducing asexually.

Gene flow is not happening, with respect to the alleles of gene G.

This is also right option because, gene flow will change allele freqeuncy.

1.b.

Frequency of dominant allele G (p) is --0.8

Freqeuncy of recessive allele g (q) is --0.2

Freqeuncy of GG genotype is -- (p^2) ---0.8 x 0.8 = 0.64