HomeworkLib
Question

1) The enthalpy of formation for H2O(l) is given by H2(g) + 1/2 O2(g) → H2O(l)....

1) The enthalpy of formation for H2O(l) is given by H2(g) + 1/2 O2(g) → H2O(l). Add this reaction to H2O(l) + 1/2 O2(g) → H2O2(aq). This is the reverse of the decomposition reaction from this experiment. Show the sum of the above two reactions is the enthalpy of formation of H2O2(aq)

2) Calculate the literature value for the enthalpy of decomposition of H2O2(aq) from the enthalpies of formation of H2O2(aq), H2O(l) and O2(g) found in your textbook or any other source

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

0 0
Add a comment
Know the answer?
Add Answer to:
1) The enthalpy of formation for H2O(l) is given by H2(g) + 1/2 O2(g) → H2O(l)....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • Part A - Calculating an Enthalpy of Reaction from Enthalpies of Formation Calculate the enthalpy change...

    Part A - Calculating an Enthalpy of Reaction from Enthalpies of Formation Calculate the enthalpy change for the reaction: 2 H2O2(l) → 2 H2O(l) + O2(g) using enthalpies of formation: ΔH∘f[H2O2]ΔH∘f[H2O]==−187.8 kJ/mol−285.8 kJ/mol Calculate the enthalpy change for the reaction: using enthalpies of formation: Multiple choice answers below: -98.0 kJ -196.0 kJ +98.0 kJ +196.0 kJ

  • Enthalpy of Formation Part 1: Part 2: Part 3: A scientist measures the standard enthalpy change...

    Enthalpy of Formation Part 1: Part 2: Part 3: A scientist measures the standard enthalpy change for the following reaction to be 591.0 kJ : 2H2O(1)—>2H2(g) + O2(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(l) is kJ/mol. A scientist measures the standard enthalpy change for the following reaction to be -2903.4 kJ: 2C2H6(g) + 7 O2(g)—>4CO2(g) + 6 H2O(g) Based on this value and the standard...

  • a) Calculate the enthalpy of the reaction 2NO(g)+O2(g)→2NO2(g) given the following reactions and enthalpies of formation:...

    a) Calculate the enthalpy of the reaction 2NO(g)+O2(g)→2NO2(g) given the following reactions and enthalpies of formation: 12N2(g)+O2(g)→NO2(g), ΔfH∘A=33.2 kJ mol−1 12N2(g)+12O2(g)→NO(g), ΔfH∘B=90.2 kJ mol−1 Express your answer with the appropriate units. b) Calculate the enthalpy of the reaction 4B(s)+3O2(g)→2B2O3(s) given the following pertinent information: B2O3(s)+3H2O(g)→3O2(g)+B2H6(g), ΔrH∘A=+2035 kJ mol−1 2B(s)+3H2(g)→B2H6(g), ΔrH∘B=+36 kJ mol−1 H2(g)+12O2(g)→H2O(l), ΔrH∘C=−285 kJ mol−1 H2O(l)→H2O(g), ΔrH∘D=+44 kJ mol−1

  • calculate enthalpy of H for the reaction N2H4(l) + 2H2O(l) -> N2(g) + 4H2)(l)

    calculate enthalpy of H for the reaction N2H4(l) + 2H2O(l) -> N2(g) + 4H2)(l) Given the reactions N2H4(l) + O2(g) -> N2(g) + 2H2O(l) Enthalpy of H = -6.22.2 kJ H2(g) + (1/2)O2(g) -> H2O(l) enthalpy of H = -285.8 kJ/mol H2(g) + O2(g) -> H2O2(l) enthalpy of H = -187.8 kJ

  • 6. Given H2(g) + 22 O2(g) → H2O(1), AH° = -286 kJ/mol, Determine the standard enthalpy...

    6. Given H2(g) + 22 O2(g) → H2O(1), AH° = -286 kJ/mol, Determine the standard enthalpy change for the reaction 2H2O(l) → 2H2(g) + O2(g) (2 pt)

  • 5. Hydrogen gas reacts with oxygen to form water. 2 H2(g) + O2(g) → 2 H2O(g),...

    5. Hydrogen gas reacts with oxygen to form water. 2 H2(g) + O2(g) → 2 H2O(g), AH=-483.5kJ Determine the mass of oxygen and hydrogen needed to produce 483 J of heat without leaving any reactant. [0.5] 6. Use standard enthalpies of formation from Appendix II.B from at the end of the textbook to determine AHºrxn for the combustion reaction of hexane (C6H14). [0.5]

  • Part A Calculate the enthalpy of the reaction 2NO(g)+O2(g)→2NO2(g) given the following reactions and enthalpies of fo...

    Part A Calculate the enthalpy of the reaction 2NO(g)+O2(g)→2NO2(g) given the following reactions and enthalpies of formation: 12N2(g)+O2(g)→NO2(g),   ΔH∘A=33.2 kJ 12N2(g)+12O2(g)→NO(g),  ΔH∘B=90.2 kJ Express your answer with the appropriate units. Part B Calculate the enthalpy of the reaction 4B(s)+3O2(g)→2B2O3(s) given the following pertinent information: B2O3(s)+3H2O(g)→3O2(g)+B2H6(g),    ΔH∘A=+2035 kJ 2B(s)+3H2(g)→B2H6(g),                            ΔH∘B=+36 kJ H2(g)+12O2(g)→H2O(l),                ΔH∘C=−285 kJ H2O(l)→H2O(g),                                          ΔH∘D=+44 kJ Express your answer with the appropriate units.

  • Calculate the enthalpy of the reaction: 2 NO(g) + O2(g) --> 2 NO2(g) given the following...

    Calculate the enthalpy of the reaction: 2 NO(g) + O2(g) --> 2 NO2(g) given the following reactions and enthalpies of formation: 1/2 N2(g) + O2(g) → NO2(g), ΔH = 33.2 kJ 1/2 N2(g) + 1/2 O2(g) → NO(g), ΔH = 90.2 kJ

  • Given the thermochemical equation for the formation of H2O by burning H2 and O2:

    Given the thermochemical equation for the formation of H2O by burning H2 and O2: H2(g) + 402 (8) → H2O (8) ΔH° = -241.8 kJ Calculate the ΔH for the following reaction: 2H2O (g) → 2 H2(g) + O2 (g) 

  • 1. A scientist measures the standard enthalpy change for the following reaction to be -2913.0 kJ:...

    1. A scientist measures the standard enthalpy change for the following reaction to be -2913.0 kJ: 2C2H6(g) + 7 O2(g)->4CO2(g) + 6 H2O(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of H2O(g) is  kJ/mol. 2. A scientist measures the standard enthalpy change for the following reaction to be -138.6 kJ : H2(g) + C2H4(g)->C2H6(g) Based on this value and the standard enthalpies of formation for the other substances, the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT