Why can't a S/T kinase phosphorylate Y and why can't a Y kinase phosphorylate S?
A. Y is too large to fit into the shallow cleft of an S/T kinase and S is too short to contact the γ phosphate of ATP in the deep cleft of a Y kinase.
B. Y is too short to fit into the deep cleft of a S/T kinase and S is too large to contact the γ phosphate of ATP in the shallow cleft of a Y kinase.
Look at the structure of serine/threonine and tyrosine. Tyrosine has an benzene ring in side chain and is an aromatic amino acids. This make tyrosine bulkier than the serine and threonine. This prevents the Y to fit into shallow cleft of an S/T by steric hindrance. Rest of the structure of is almost same between the S/T and Y.
So option A, (Y is too large to fit into the shallow cleft of S/T kinase and S is too short to contact the Y phosphate of ATP in deep cleft of Y kinase) is the correct answer.
Why can't a S/T kinase phosphorylate Y and why can't a Y kinase phosphorylate S? A....
r the recurrence relation o. Consider T(n) = Vn T(Vn) + n a. Why can't you solve this with the master theorem? b. S t involves a constant C, tell me what it is in terms of T(O), T(1), or whatever your inequality by induction. Show the base case. Then show the how that T( n)= 0(n lg ig n). First, clearly indicate the inequality that you wish to hen proceed to prove the inductive hypothesis inductive case, and clearly...
What is the correct answer? And please explain
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2-3 sentences on why it is the correct answer for each,
thank you !
15. Which statement below about the interconversion of the alpha and beta anomers of D-glucopyranose is true? The interconversion requires an enzyme called an isomerase The interconversion is spontaneous in water because the acetal functionality is labile The interconversion is spontaneous in water but is slow which is why we typically draw glucose having one anomeric form...
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