Question

Write a function name ‘findNumber’ that will receive three parameters: the first one is an int one-dimensional array ‘arr’, the second one is an integer ‘n’ that represents the number of elements in the array and the third one is an integer ‘x’. Using POINTERS search the array ‘arr’ for the first occurrence of that number ‘x’. If you find the number, return the position of the number in the array; otherwise return -1.

For example if the array contains the numbers: 10, 20, 60, 5, 60 and you search for the number 60, then the function should return 2.

Answer 1

ANSWER:

#include <stdio.h>

int findNumber(int arr[],int n,int x)
{
int *ptr=arr; //pointer pointing to 1st element of array
int i=0;
for(i=0;i<n;i++)   
{
if(*ptr==x) //if ptr pointing value is x return position
{
return i;
}
ptr++; //increment ptr to point to next value in array
}
return -1; //if number doesnt match to any value in array returning -1
}
int main()
{
int n,x;
printf("Enter number of elements in array:"); //n value from keyboard
scanf("%d",&n);
int arr[n];
printf("Enter elements into array:");
for(int i=0;i<n;i++)
{
scanf("%d",&arr[i]); //array values from keyboard
}
printf("Enter element to search:");
scanf("%d",&x); //x value from keyboard
int pos=findNumber(arr,n,x); //function call
printf("position=%d",pos);
return 0;
}

//if any doubt please verify below pic

OUTPUT:

//if element in array

//if element not in array