When Benzoic acid is combusted, -3226.6 kJ/mol of heat is released. Calculate the heat of formation...
When Benzoic acid is combusted, -3226.6 kJ/mol of heat is released. Calculate the heat of formation for benzoic acid. Show all steps.(Benzoic acid = C7H6O2 )
Thanks!!
Homework Answers
Combustion reaction of Benzene is:
2 C6H5COOH + 15 O2 —> 14 CO2 + 6 H2O .
C6H5COOH + 15/2 O2 —> 7
CO2 + 3 H2O . 
Hcomb
= -3226.6 kJ
From literature
Hf(O2)
= 0.0 kJ/mol
Hf
(CO2) = -393.51 kJ/mol
Hf(H2O)
= -285.8 kJ/mol
Hf(
C6H5COOH ) = ?
From reaction
Hcomb
= Hf(
products) - Hf(reactants)
Hcomb
= (3*Hf(H2O))
+ (7*Hf
(CO2)) - Hf(
C6H5COOH ) - (15/2 * Hf(O2))
-3226.6 kJ/mol = (3*(-285.8)) + (7*(-393.51)) - Hf(
C6H5COOH )
Hf(
C6H5COOH ) = -3611.97-3226.6 = -
385.37 kJ/mol
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