A small ball has a mass m = 4.0 x 10^-8 kg and a charge of q = -2.0 x 10^-5 C. It enters a box with an initial speed of v0 = 1.0 x 10^4 m/s. The point where the charge leaves the box has an electrical potential 350 x 10^3 higher than the entry point.
(a) Find the speed of the ball as it leaves the box.
(b) Suppose that the charge on the ball were q = +2.0 x 10-5 C. With what speed would the ball leave the box in this case?
Problem 2: An imaginary particle π has mass m 5 x 10-27 kg and charge q +3c 4.8x 10-19 C. Compare the magnitude of the electric repulsion between two π particles with that of gravitational attraction between them. Problem 3: Two equal charges 22 x 10-6 C are located at -0, y 0.3 m and z 0, V0.3 m respectively. What are the magnitude and direction of the total electric force that q1 and g2 exert on a third charge...
A small particle has charge q and mass 2.00×10-4 kg. It moves from point A, where the electric potential is VA = +400 V, to point B, where the electric potential is VB = +800 V. The electric force is the only force acting on the particle. The particle has speed 5.00 m/s at point A, and a speed of 4.25 m/s at point B. What is the charge of the particle q?
A charged particle of mass m = 4.0 x 10- kg, initially moving with constant velocity in the y-direction, enters a region containing a constant magnetic field B = 4.0 T aliged with the positive z-axis as shown below. The particle enters the region at (x, y) = (d, 0) and leaves the region at (r,y)= (0, d), d = 0.5 m at a time t 600 is after it entered the region. d Figure 1 (a) With what speed...
Three point charges are placed at the following (x, y) coordinates:+4.0*10^-6 C charge at(0, .5m), charge +1.0*10^-6 C at(.2m, 0), and charge -5.0*10^-6 C at(.2m, .5m). Calculate the electrical potential at the origin due to these three point charges. Take the zero of potential to be at infinity
A small object has a mass of 4.0 × 10-3 kg and a charge of -29C. It is placed at a certain spot where there is an electric field. When released, the object experiences an acceleration of 3.8 × 103 m/s2 in the direction of the +x axis. Determine the electric field, including sign, relative to the +x axis.
A 4.0 kg cart with a charge of 4.0 x 10 -5 C starts at rest on a horizontal frictionless surface 0.50 m from a fixed object with a charge of 2.0 x 10-4 C. When the cart is released. How fast is the cart moving when it has traveled 2.0 m? How fast is it moving when it is very far away from the fixed object? I know the answers are (7.35 m/s, 8.5 m/s) but not how to...
Two Dimensional Forces CL-5 A small ball that has a mass m 6.00x10 kg and a net charge q is hanging from a string. When a second charge Q-+5uC is brought near the ball, it holds the ball at rest in the position shown in the figure. In this position the string makes an angle of 35.0 with the vertical and Qis 0.250m from the small ball. a) Draw the free body diagram for the ball and apply Fne-ma to...
(7.) A particle with a charge of +2.0 mC and a mass of 5 x 10-6 kg passes through point A with a speed of 20 m/s and through point B with a speed of 50 m/s. Using the principle of conservation of energy, find (VA – VB), the potential difference between the points A and B. Which point is at a higher potential? Does your answer make sense? Explain. [10 points]
A particle of a mass 1.2 x 10-11 kg and negative charge – 1.0 °C moves to the right with a speed of 3.0 x 103 m/s. It enters a uniform electric field region where the field is known to be parallel to particle's direction of motion. If the particle is to be brought to rest in the space of 4.0 cm, (a) What potential difference does it have to go through to stop this way? (b) what is the...
Help and explain please
A particle of a mass 1.2 x 10-11 kg and negative charge - 1.0 uC moves to the right with a speed of 3.0 x 103 m/s. It enters a uniform electric field region where the field is known to be parallel to particle's direction of motion. If the particle is to be brought to rest in the space of 4.0 cm, (a) What potential difference does it have to go through to stop this way?...