For extraction : lets say weight of benzoic acid- 10ml, molarity of benzoic acide solution is .02 moles, milliliters of NaOH solution (average) is 12 ml, molarity of NaOH solution is .017 M, how do i find the solution to the questions below?? thanks
-so in titration of NaOH, i have milliliters of NaOH for aqueous layer of 15 ml, how do i find the millimoles of benzoic acid left in aqueous layer?
-B.) how do i find the millimoles of benzoic acid in CH2Cl2 layer?
-c) how do i do the calculation Kd?
For extraction : lets say weight of benzoic acid- 10ml, molarity of benzoic acide solution is...
How many moles of acetic acid could be in the 25% acetic acid solution before the extraction occurs? 100% acetic acid has 0.0394 moles present. 0.00985 moles 0.985 moles 0.158 moles Calculate how many moles of acetic acid were present in the aqueous layer after the extraction of 5% acetic acid. Use the data from the titration below to calculate your answer. Titration data: 0.1000M NaOH, 1.45 mL used to reach end point of titration. Group of answer choices 0.000795...
Calculate how many moles of acetic acid were present in the aqueous layer after the extraction of 5% acetic acid. Use the data from the titration below to calculate your answer. Titration data: 0.1000M NaOH, 1.45 mL used to reach end point of titration. Group of answer choices 0.000795 moles 0.725 moles 0.000145 moles
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with a strong base. The concentration of NaOH is 0.100 M. A. Based on this graph given below, determine the Ka. B. Determine the molarity of the acid. Benzoic acid titration with 0.1 M NaOH 12.00 10.00 8.00 6.00 4.00 2.00 0.00 0.00 5.00 10.00 15.00 Volume of NaOH mL
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with a strong base. The concentration of NaOH is 0.100 M. A. Based on this graph given below, determine the Ka. B. Determine the molarity of the acid. Benzoic acid titration with 0.1 M NaOH 12.00 10.00 8.00 pH 6.00 4.00 2.00 0.00 0.00 5.00 10.00 15.00 Volume of NaOH mL
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with a strong base. The concentration of NaOH is 0.100 M. A. Based on this graph given below, determine the Ka. B. Determine the molarity of the acid. Benzoic acid titration with 0.1 M NaOH 12.00 10.00 8.00 6.00 4.00 2.00 0.00 0.00 5.00 10.00 15.00 Volume of NaOH mL
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with a strong base. The concentration of NaOH is 0.100 M. A. Based on this graph given below, determine the Ka. B. Determine the molarity of the acid. Benzoic acid titration with 0.1 M NaOH 12.00 10.00 8.00 6.00 4.00 2.00 0.00 0.00 5.00 10.00 15.00 Volume of NaOH mL
please solve number 5 and 6 using the table.
Part 1: Simple Extraction and Determination of the Distribution Coefficient (Partition Coefficient) for Propionic Acid Between Ether and Water Table 1 (a) Preparation of Propionic Acid (PA) Solution weight PA Volume H2O (g) (e) Titration of Aqueous Propionic Solution After Ether Extraction (b) Titration of Aqueous Propionic Acid Solution Before Ether Extraction Volume PA. Volume NaOH Volume Volume PA Aliquot (mL) aliquot (mL) NaOH (mL) (mL) (mL) 17.30 mL50.00 mL 10-00...
separation of benzoic acid and napthalene by extraction lab
2. You are given a two-phase system containing an aqueous layer and an organic layer, but you don't know which is which, nor do you know the identity of the organic solvent. How could you determine which layer is the aqueous layer?
separation of benzoic acid and napthalene by extraction lab
2. You are given a two-phase system containing an aqueous layer and an organic layer, but you don't know which is which, nor do you know the identity of the organic solvent. How could you determine which layer is the aqueous layer?
Draw the reaction mechanism with chemical structures in the separation of naphthalene and benzoic acid by extraction. 1g of Naphthalene/benzoic acid mixture is dissolved in 15 mL dichloromethane, transferred to a separatory funnel where 10 mL 2.5M NaOH(aq) is added. Organic and Aqueous layers are separated, and 12M HCl(aq) is added to the aqueous layer while cooling, forming a precipitate, which is vacuum filtrated. Don't understand how to draw each chemical structure!