Question

aList = [1, 'Mercy', 20, 'Cyber', 300].

a) Write a single line of Python statement to print the value 20 from aList.

b) Write a single line of Python statement to print the character b from aList.

c) Write a single line of Python statement to print erc from aList.

d) Write a Python segment that print a sequence number starting from 1 followed by ")" and an element for each element of the list. Use a for loop and format function. So it should display

1) 1

2) Mercy

3) 20

4) 300

5) bbdcc

e) Write a Python function that counts a character from a list. The function countChar() takes a character and a list. A list contains numbers and text as illustrated above. Please fill in the blank below:

char = 'c'

aList = [1, 'Mercy', 20, 300, 'bbdcc']

def countCha(char,list):

i=0

for e in list:

   if str(e).isdigit():

     _____________

   else:

     for ______ in e:

       if ea == char:

          _____________

return i

print("{} has {} times of {}".format(aList, ________________, char))

In this case, the outcome of the print statement will be

[1, 'Mercy', 20, 300, 'bbdcc'] has 3 times of c

Answer 1

aList = [1, 'Mercy', 20, 'Cyber', 300]

# a) Write a single line of Python statement to print the value 20 from aList.

print(aList[2])

# b) Write a single line of Python statement to print the character b from aList.

print(aList[3][2])

# c) Write a single line of Python statement to print erc from aList.

print(aList[1][1:4])

# d) Write a Python segment that print a sequence number starting from 1 followed by ")" and an element for each element of the list. Use a for loop and format function. So it should display

for i in range(0,len(aList)):

print(str(i+1)+")",aList[i])

# e) Write a Python function that counts a character from a list. The function countChar() takes a character and a list. A list contains numbers and text as illustrated above. Please fill in the blank below:

char = 'c'

aList = [1, 'Mercy', 20, 300, 'bbdcc']

def countCha(char,list):

i=0

for e in list:

if str(e).isdigit():

i = i # do nothing there is no 'c' when e is digit

else:

for ea in e:

if ea == char:

i += 1

return i

print("{} has {} times of {}".format(aList, countCha(char,aList), char))