1. Maltose, trehalose, and cellobiose are all disaccharides of glucose that differ in the nature of the glycosidic bond attaching the two glucosyl residues. In maltose, the linkage is α(1→4); in trehalose, the linkage is α(1→1); in cellobiose the linkage is β(1→4). Based upon this information, answer the followingquestions:
1a. Which of these disaccharides is a non-reducing sugar? Explain your reasoning.
1b. Which of these disaccharides results from the breakdown of cellulose? Explain your reasoning.
1c. Which of these disaccharides results from the breakdown of amylose? Explain your reasoning.
1a .
Nonreducing disaccharides trehalose have glycosidic bonds between their anomeric carbons and thus cannot convert to an open-chain form with an aldehyde group and hence they are stuck in the cyclic form.
1b .
Maltose is formed due to the breakdown of cellulose . Cellulose is made of glucose (beta) monomeric units . Since Maltose is made up of 2 glucose molecules, the answer is maltose.
1c .
Amylose is again a polymer of glucose . They are linked by alpha 1-4 linkages. Hence the disaccharide is Maltose .
1. Maltose, trehalose, and cellobiose are all disaccharides of glucose that differ in the nature of...
1. Maltose, trehalose, and cellobiose are all disaccharides of glucose that differ in the nature of the glycosidic bond attaching the two glucosyl residues. In maltose, the linkage is α(1→4); in trehalose, the linkage is α(1→1); in cellobiose the linkage is β(1→4). Based upon this information,which of these disaccharides is a non-reducing sugar? Explain your reasoning. Which of these disaccharides results from the breakdown of cellulose? Explain your reasoning. Which of these disaccharides results from the breakdown of amylose? Explain...
1. Using the free energy change equation, solve the following questions assuming ∆H = 15,000 J and ∆S =50 J/K [provide solutions, not just answers] 1a. Is this reaction spontaneous at 20oC? 1b. Is the above reaction spontaneous at 40oC? 1c. At what temperature Celsius would the above reaction be at equilibrium? 1d. If the temperature of the reaction was 0oC and the ∆H = 15,000 J, what would the ∆S need to be for the reaction to be at...