A 2.56 gram sample of an unknown white solid was dissolved in water, making 450.0 mL of solution. At 25 °C, the solution exhibited an osmotic pressure of 0.407 atm. What is the molar mass of the solute? What would the boiling point elevation be for this solution (again assuming molarity and molality are essentially the same in this dilute solution)?
(answer should be 342 g/mol; 0.00852 °C.)
A 2.56 gram sample of an unknown white solid was dissolved in water, making 450.0 mL...
5. 1.024 g of an unknown molecular solid are dissolved in enough
water to produce 200.0 mL of solution. The osmotic pressure at 25C
is 278.0 torr. What is the molar mass of the solid?
6a. Calculate the van't Hoff factor of a 0.085M potassium
sulfate solution that has an osmotic pressure of 5.4atm at
25C
5. 1.024 g of an unknown molecular solid are dissolved in enough water to produce 200.0 ml. of solution. The osmotic pressure at 25...
5. 1.024 g of an unknown molecular solid are dissolved in enough water to produce 200.0 mL of solution. The osmotic pressure at 25°C is 278.0 torr. What is the molar mass of the solid? 1342.5 g/mol
ill give good rating d) A 2.15 g sample of molecular solid was dissolved in 25.0 g of CS2. The boiling point elevation of the solution was 1.59°C. Find the molar mass of the unknown. (Kb of CS2 is 1.07°C/m) e)What is the molality of C6H4Cl2 in a solution prepared by dissolving 2.97 g of C6H4Cl2 in 966 g of ethanol? f) The percent by mass of sodium sulfate in a solution of 32.0 g of sodium sulfate dissolved in...
3a. Calculate the molar mass (in g/mol) of an unknown 1:1 electrolyte if 0.482 g dissolved in 223.1 mL of water at 74.75 °C has an osmotic pressure of 54.4 mmHg. R = 0.082058 L⋅atm⋅mol−1⋅K−1. 1.00 atm = 760 mmHg. Report your answer to THREE significant figures. 3b. Calculate the required mass of an unknown nonelectrolyte (ℳ = 131.5599 g/mol) dissolved in 140.1 g of solvent that gives a solution that boils at 36.04 °C. The boiling point of the...
A 4.75-g sample of an unknown compound is dissolved in enough water to make 100.0 mL of solution. This solution has an osmotic pressure of 25.0 torr at 25oC. Find the molar mass of the unknown.
A 275 mg sample of a nonelectrolyte compound was dissolved in water to produce 10.0 mL of a solution at 25°C. The osmotic pressure of this solution was measured and found to be 3.67 atm. What is the molar mass of this compound? O 183 g/mol 18.3 g/mol 101 g/mol 1560 g/mol 1830 g/mol Question 25 (1 point) Which statement below is true? O Nonpolar molecules can dissolve in polar solvents. Gases are soluble only in nonpolar solvents. lonic compounds...
A 1.53 gram sample of an unknown monoprotic acid is dissolved in 25.0 mL of water and titrated with a a 0.234 M aqueous barium hydroxide solution. It is observed that after 16.3 milliliters of barium hydroxide have been added, the pH is 4.924 and that an additional 10.0 mL of the barium hydroxide solution is required to reach the equivalence point. (1) What is the molecular weight of the acid? g/mol (2) What is the value of Ka for the...
A 1.20 gram sample of an unknown monoprotic acid is dissolved in 25.0 mL of water and titrated with a a 0.485 M aqucous potassium hydroxide solution. It is observed that after 7.33 milliliters of potassium hydroxide have been added, the pH is 4.515 and that an additional 13.3 mL of the potassium hydroxide solution is required to reach the equivalence point. (1) What is the molecular weight of the acid? (2) What is the value of K, for the...
A 1.48 gram sample of an unknown monoprotic acid is dissolved in 30.0 mL of water and titrated with a a 0.291 M aqueous barium hydroxide solution. It is observed that after 7.15 milliliters of barium hydroxide have been added, the pH is 9.104 and that an additional 13.2 mL of the barium hydroxide solution is required to reach the equivalence point. (1) What is the molecular weight of the acid? g/mol 2) What is the value of K_a for...
A 0.660 gram sample of an unknown monoprotic acid is dissolved in 30.0 mL of water and titrated with a a 0.370 M aqueous potassium hydroxide solution. It is observed that after 10.1 milliliters of potassium hydroxide have been added, the pH is 7.732 and that an additional 5.10 mL of the potassium hydroxide solution is required to reach the equivalence point. (1) What is the molecular weight of the acid? _______ g/mol (2) What is the value of Ka...