Question

can someone please explain why 333 22 1 is printed on the screen? i have an idea as to why but it would help if an expert could explain why.

int main()
{
   for (int i = 3; i > 0; i--) {
       for (int j = 1; j <= i; j++) {
           cout << i;
       }
       cout << endl;
   }
   system("pause");
}

Answer 1

for (int i = 3; i > 0; i--) {
    for (int j = 1; j <= i; j++) {
        cout << i;
    }
    cout << endl;
}

i = 3
    j = 1
        prints i -> prints 3
    j = 2
        prints i -> prints 3
    j = 3
        prints i -> prints 3
    then prints a new line
    so, it prints 333 when i=3
i = 2
    j = 1
        prints i -> prints 2
    j = 2
        prints i -> prints 2
    then prints a new line
    so, it prints 2 when i=2
i = 1
    j = 1
        prints i -> prints 1
    then prints a new line
    so, it prints 1 when i=1
    

then loop exists because i = 0 and (i > 0) is false

Output:
---------
333
22
1