6) A 0.25 kg mass is hanged from a string with length L = 0.65 m, making a pendulum. The mass is raised so that the taut string makes an angle of θ = 37◦ with the vertical, and then released from rest. When the mass swings past the bottom (where its speed is maximum) it is observed to have a speed of 1.1 m/s. a) Choosing the bottom as your h = 0 level, what is the initial height of the mass? (This just requires drawing a figure and applying geometry + trigonometry, not physics, but it will help for the next question). b) Was the air resistance force negligible for the motion of the mass? Explain why or why not, and if not, find the work it did.
6) A 0.25 kg mass is hanged from a string with length L = 0.65 m,...
A mass M = 4 kg attached to a string of length L = 2.0 m swings in a horizontal circle with a speed V. The string maintains a constant angle theta θ= 46.5 degrees with the vertical line through the pivot point as it swings. What is the speed V required to make this motion possible?
he length of a simple pendulum is 0.65 m and the mass of the particle (the “bob”) at the end of the cable is 0.20 kg. The pendulum is pulled away from its equilibrium position by an angle of 7.7° and released from rest. Assume that friction can be neglected and that the resulting oscillatory motion is simple harmonic motion. (a) What is the angular frequency of the motion? (b) Using the position of the bob at its lowest point...
A m = 3.50-kg mass swings as a pendulum on a 38.5 m long string. (a) The mass is released from rest when the string is at an angle of 35.0° from the vertical. Find its speed at the bottom of the swing. m/s (b) What would be the speed the mass at the bottom of the swing if it had a speed of 6.00 m/s when the string is at an angle of 35.0° from the vertical. m/s
A m = 3.50-kg mass swings as a pendulum on a 37.0 m long string. (a) The mass is released from rest when the string is at an angle of 41.0° from the vertical. Find its speed at the bottom of the swing. m/s (b) What would be the speed the mass at the bottom of the swing if it had a speed of 4.60 m/s when the string is at an angle of 41.0° from the vertical. m/s
A m = 3.50-kg mass swings as a pendulum on a 32.5 m long string. (a) The mass is released from rest when the string is at an angle of 40.0° from the vertical. Find its speed at the bottom of the swing. m/s (b) What would be the speed the mass at the bottom of the swing if it had a speed of 6.00 m/s when the string is at an angle of 40.0° from the vertical. m/s
A 0.25 kg ball is suspended from a light 1.1 m string as shown. The string makes an angle of 21° with the vertical. Let U = 0 when the ball is at its lowest point (θ = 0). 1. What is the gravitational potential energy, in joules, of the ball before it is released? 2. What will be the speed of the ball, in meters per second, when it reaches the bottom?
A mass M = 4 kg attached to a string of length L = 2.0 m swings in a horizontal circle with a speed V. The string maintains a constant angle 0 = 44.1 degrees with the vertical line through the pivot point as it swings. What is the speed V required to make this motion possible?
7. Alex attaches a small pendulum bob of mass m to a string of length L. James holds the bob so that the string is horizontal and then releases it from rest. At the lowest point of the swing, the string catches on a thin peg a distance R above the lowest point. Show that R must be smaller than 2 if the string is to remain taut as the bob swings around the peg in a full circle Ri
A small mass m is hung at the end of a light string of length 1.5 m and allowed to swing over a small amplitude as a simple pendulum. It is observed that the amplitude of swing is reduced to half its initial value in 30 complete swings. It may be assumed that the reduction of amplitude is due entirely to resistance of the air and this in turn may be assumed to be proportional to the velocity of the...
a mass of 1.5 kg swings on teh end of a pendulumn with a length of .4 m. the pendulum bob is released from rest when the string makes an angle of 30 degrees with respect to the vertical. find the speed of the bob as it passes through the center point at the bottom if the arc. A) Use the bottom most point of the arc as a refernce point for the PE. B) Use where the string connects...