why is the lens equation written in the form y=mx+b as 1/di=-1/do +1/f? PLEASE EXPLAIN WHY!
The equation of the line that goes through the point ( 3 ,5 ) and is parallel to the line 2 x + 4 y = 2 can be written in the form y = mx+b where m is and where b is?
Explain the elements of a regression equation for a simple linear regression: Y=b+mx. Why are regression analysis useful? Give an example.
Q2)a) [5pt] Find the equation of the line in the plane (in y = mx +b form) that is perpendicular to the line y = 1/5x + 17 and goes through the point (9, 12). Equation of the line: _______ Q2)b) [5pt] Find the equation of the line in the plane that is perpendicular to the y axis and goes through the point (-2,4). Equation of the line:_______
(1 point) The equation z2 can be written in the form y'-f(y/z), ie., it is homogeneous, so we can use the substitution u-y/z to obtain a separable equation with dependent variable Introducing this substitution and using the fact that y' zuu we can write (*) as u u- f(u) where f(u) Separating variables we can write the equation in the form dz where g(u)- An implicit general solution with dependent variable u can be written in the form In(z) Transforming...
The equation y' 6x2 + 3y2 ту can be written in the form y' = f(y/x), i.e., it is homogeneous, so we can use the substitution u = y/x to obtain a separable equation with dependent variable u= u(x). Introducing this substitution and using the fact that y' = ru' + u we can write (*) as y' = xu'+u = f(u) where f(u) = Separating variables we can write the equation in the form dr g(u) du = where...
(1 point) The equation 3ry2r 2y2 (*) can be written in the form y f(y/x), ie., it is homogeneous, so we can use the substitution u = y/x to obtain a separable equation with dependent variable uu(x. Introducing this substitution and using the fact that y' ru' u we can write () as y xu'w = f(u) where f(u) Separating variables we can write the equation in the form da np (n)6 where g(u) = An implicit general solution with...
Let f(x)=2sinx/2sinx+4cosx. Then f′(x)= . The equation of the tangent line to y=f(x) at a=π/2 can be written in the form y=mx+b where m= b=
Question 4 Determine the focal length of the lens from the following graphs[1/do + 1/di = 1/f] 1/d, vs. 1/d. 0.0350 0.0300 y = -0.9863x + 0.0419 0.0250 0.0200 1/d, 0.0150 • 1/di-Lens 1 0.0100 Linear (1/di-Lens 1) 0.0050 0.0000 0.0000 0.0050 0.0100 0.0250 0.0300 0.0350 0.0150 0.0200 1/d, 1. 0.0419 cm 2.1 12 cm 24 cm 4 0.9581 cm
When answering the question please explain the steps on how to
form y=mx+b. I know how to make the graph, but im confused on how
to calculate everything. thanks !
The data in the chart below is for the distance (in cm) to the near point, the point nearest the eye at which the eye can accurately focus, at a person's age. Near Point Age (years) (cm) 7.5 10 9 20 11.5 30 17.2 40 52.5 50 83.3 60 Make...
The equation 4zy + z² + y2 4y can be written in the form y = f(y/2). Le it is homogeneous so we can use the substitution y/z to obtain a separable equation with dependent variable u = Introducing this substitution and using the fact that y zu' + u we can write (.) as y = Du' +u = f(u) where f(u) Separating variables we can write the equation in the form dr g(u) du I where g(u) An...