A box contains 9 balls numbered from 3 to 11. If 4 random balls are selected...
A box contains 9 balls numbered from 3 to 11. If 4 random balls are selected (without replacement), what is the probability that the sum of the numbers is even? (explain please)
Thanks for the help
Homework Answers
Total number pf ways of selecting 4 balls out of 9 is C(9,4) = 126
Total ways the sum is even is
1. All numbers are even (4,6,8,10) = 1 way
2.
Two numbers are even and two are odd = C(5,2)*C(4,2) = 10*6 = 60 ways
3.
All four number are odd = C(5,4) = 1 way
P(sum of numbers is even) = 62/126 = 0.4921
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