A box contains 9 red balls and nine numbered balls from 1 to 9, six balls are selected at random from the box. What is the probability that two of the selected balls will be red and three balls will be numbered serially?؟؟؟؟
Six balls are selected at random from the box of 9+9=18 balls in
ways.
The number of ways of selecting 2 red balls from 9 is
.
The number of ways that three balls will be numbered serially
(123,234,345,456,....., 789) is
The remaining 1 ball can be selected from rest 7+6 balls in
ways.
The required probability is

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