The kinetic friction force between a 9.6-kg object and a horizontal surface is 91 N. If the initial speed of the object is 62 m/s, what distance will it slide before coming to a stop?
Using work energy theorem,
0.5 mv^2 = Fd
0.5 x 9.6 x 62^2 = 91 x d
Distance, d = 202.76 m
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