Balance the following redox reaction in acidic solution and show the net ionic equation.
AgCI + NO ---> Ag + CL- + NO3-
Given reaction AgCI + NO ---> Ag + Cl- + NO3-
1) Oxidation half reaction 1) Reduction half reaction
NO -------> NO3- AgCI --------> Ag + Cl-
2) Balance the oxygen atoms by adding H2O 2) No oxygen atoms are there, so no balance is required
NO + 2H2O -------> NO3-
3) Balance the hydrogen atoms by adding H+ 3) No hydrogen atoms are there, so no balance is required
NO + 2H2O -------> NO3- + 4H+
4) Balance the charge by adding electrons 4) Balance the charge by adding electrons
NO + 2H2O -------> NO3- + 4H+ + 3e- AgCI + e- --------> Ag + Cl-
5) Multiply the oxidation half reaction with 1 and reduction half reaction with 3
NO + 2H2O -------> NO3- + 4H+ + 3e-
3AgCI + 3e- --------> 3Ag + 3Cl-
6) Cancel the electrons on both sides and write the sum of two reactions
3AgCI + NO + 2H2O -------> 3Ag + 3Cl- + NO3- + 4H+
Therefore, balanced equation is
3AgCI + NO + 2H2O -------> 3Ag + 3Cl- + NO3- + 4H+
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