A wildtype female fly ends up mating with a male carrying a Y-linked allele that causes...
A wildtype female fly ends up mating with a male carrying a Y-linked allele that causes antennapedia. If their F1 progeny cross, what will be the expected ratio of F2 antennapedia flies to wildtype? Would it be 100% or 50% or neither something like 25% or 0%?
Homework Answers
It is given that disease is linked to the Y allele. That's why this is the case of Y linked inheritance. Let c allele encodes disease which is present on Y chromosome.
Now the genotype of parents are:
XX ( wild female) × XYc ( antenapedia male)
Punnet square:
Now there is found crossing between F1:
Parents: XX ( normal) × XYc ( antenapedia)
That's why there is found disease in two offspring out of 4.
The expected ratio of wild type to the antenapedia offspring is
(2/2 ) ×100=100%
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