a 55-Kg box rests on a horizontal surface. The coefficient of static friction between the box...
a 55-Kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.30. A horizontal 42 N force is applied to the box. what is the static friction force on the box? (I know that the answer is 42 N because my teacher told me but I need the 4 questions below answered regarding this question)
1) what is the minimum static friction force?
2) how do you calculate the maximum friction force?
3) if an object is at rest before a force is applied at what point does the object starts moving?
4) Explain why the answer is 42 N?
can you please answer these in order and indicate which one is for what number. Thank You!
Homework Answers
When applied force is minimum to static friction force then applied force acts as static friction force .
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