A 2.49?g particle moves at 2.03×108 m/s. What is its momentum?
A 2.47?g particle moves at 2.09×10^8 m/s. What is its momentum?
A 1.30-kg particle moves in the xy plane with a
velocity of = (4.10
î − 3.80 ĵ) m/s. Determine the
angular momentum of the particle about the origin when its position
vector is = (1.50
î + 2.20 ĵ) m.
A 1.92-kg particle has a velocity (2.03 İ-2.90 ) m/s, and a 2.99-kg particle has a velocity (0.98 İ + 5.99 ) m/s. (a) Find the velocity of the center of mass. j) m/s (b) Find the total momentum of the system. j) kg m/s 10 9 A OP 035 M A 5.10-kg steel ball strikes a wall with a speed of 11.0 m/s at an angle of θ 60.0° with the surface. It bounces off with the same speed...
If a particle with mass m moves with position ! r(t), then, the angular momentum is defined as ! L(t) = m! r(t) × ! v (t) and its torque is ! τ (t) = m! r(t) × ! a(t). Show that ! L′(t) = ! τ (t) . What are the consequences for both ! a(t) and ! L(t) when ! τ (t) = ! 0 for all t? THIS IS CALC 3 VECTOR STUFF MUST USE CALCULUS
A spaceship moves by Earth at 2.6 × 108 m/s. A satellite moves by Earth in the opposite direction at 1.7 × 108 m/s. 1)Use the Galilean transformation to calculate the speed of the satellite relative to the spaceship. (Express your answer to two significant figures.)
A 1.5 g particle has momentum 4.0×105 kg⋅m/s What is the particle's speed? Express your answer using two significant figures.
A 1.5 g particle has momentum 5.0×105 kg⋅m/s What is the particle's speed? Express your answer as a fraction of c. v/c= ?
A 5.71 kg particle-like object moves in a plane with velocity components vx = 16.9 m/s and vy = 51.5 m/s as it passes through the point with (x, y) coordinates of (9.95, -7.85) m. Just then, in unit-vector notation, what is its angular momentum relative to (a) the origin and (b) the point (-6.87, -6.87) m?
A particle (q = 5.0 nc, m = 3.0 mu g) moves in a region where the magnetic field has components, B_x = 2.0 mT, B_y = 3.0 mT, and B_z =-4.0 mT. At an instant when the speed of the particle is 5.0 km/s and the direction of its velocity is 120 degree relative to the magnetic field, what is the magnitude of the acceleration of the particle?
A particle with a mass of 9 kg moves in a circle with a radius of 0.18 m and a tangential speed of 13 m/s. What is the angular momentum of the particle in kg-m2/s?