Hess’s Law (a) Calculate the ∆H for the reaction: CCl4(g) → C(s, graphite) + 2Cl2(g) using...
Hess’s Law (a) Calculate the ∆H for the reaction: CCl4(g) → C(s, graphite) + 2Cl2(g)
using the following chemical equations and their respective enthalpy changes:
C(s, graphite) + 2F2(g) → CF4(g) ∆H = -679.9 kJ
CF4(g) + 2Cl2(g) → CCl4(g) + 2F2(g) ∆H = 573.2 kJ
(b) Calculate the ∆H for the reaction: C(s, graphite) + 2H2O(g) → CH4(g) + O2(g)
using the following chemical equations and their respective enthalpy changes:
C(s, graphite) + O2(g) → CO2(g) ∆H = -394 kJ
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g) ∆H = -802 kJ
Homework Answers
a) Let; we have given;
C(s, graphite) + 2F2(g)
CF4(g)
H
=-679.9kJ ------(1)
CF4(g) + 2Cl2(g)CCl4(g)
+ 2F2(g) H
= 573.2kJ ----(2)
Reversing (1) and (2) and adding we get;
CF4(g)
C(s, graphite) + 2F2(g)H
=+679.9kJ ------(3) new reaction
CCl4(g) + 2F2(g)CF4(g)
+ 2Cl2(g)H
= -573.2kJ ----(4) new reaction
------------------------------------------------------------------
CCl4(g)
C(s, graphite) + 2Cl2(g)
H =+106.7kJ
b) Let; we have given;
C(s, graphite) + O2(g)
CO2(g)H
=-394kJ ------(1)
CH4(g) + 2O2(g)
CO2(g) +
2H2O(g) H
= -802kJ ----(2)
Reversing (2) and adding we get;
C(s, graphite) + O2(g)
CO2(g)H
=-394kJ ------(1)
CO2(g) + 2H2O(g)
CH4(g) + 2O2(g) H
= +802 kJ ----(3) new reaction
------------------------------------------------------------------
C(s, graphite) + 2H2O(g)
CH4(g) + O2(g)
H =+408kJ
Add Answer to:
Hess’s Law (a) Calculate the ∆H for the reaction: CCl4(g) → C(s,
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