Question

1.Write a bash script A5p1.sh to output the number of executable and non-executable files and subdirectories separately in the directory that is specified as the first command line argument to this script. Do not count recursively in subdirectories. Do not call any external Linux utilities such as “ls”.

2.Write a bash script A5p1.sh to output the number of executable and non-executable files and subdirectories separately in the directory that is specified as the first command line argument to this script. Do not count recursively in subdirectories. Do not call any external Linux utilities such as “ls”.

Answer 1

Hey, It is a very interesting problem where we don't have to use in-build methods and hence the problem becomes challenging. For simplicity purposes, I had divided the solution into parts. So, let's start:

PART ONE: REQUIREMENTS:

The problem statement is pretty clear that we need to find the number of executable and non-executable files in a directory using a bash script.

The use of inbuild methods or utilities is not allowed for this problem.

PART TWO: APPROACH

For solving this specific problem I am using the approach as described below:

STEP 1: Initialize two counters, one for executable files and directories and one for non-executable files and directories.

STEP 2: Iterate over all the files and directories under the specified path.

STEP 3: Check whether the file is executable or not

STEP 4: Repeat the steps until no file or subdirectory exists.

STEP 5: make sure the steps don't count the recursive files and directories.

PART THREE: IMPLEMENTATION:

I will provide the text code at the end of the explanation.

STEP 1: Variables

STEP 2: Iterating over each item

STEP 3: Printing the result:

PART FOUR: SAMPLE INPUT-OUTPUT:

There was a folder named ABC inside folder a but that was not processed because we don't want recursive computations.

PART FIVE: SOURCE CODE:

Please read all the comments from the code.

Please read the code in a modular fashion for better understanding.

**********************CODE**********************

#!/bin/bash

#Counter to hold the executable files and directories

executable_counter=0

#Counter to hold the non-executable files and directories

nonexecutable_counter=0

#All the items in a specified directory but not recursively

ITEMS=*

#Iterating all the items

for file in $ITEMS

do

#Check whether executable tag is found or not

if [[ -x "$file" ]]

then

#Yes found

echo "'$file' is executable"

#Incrementing Counter

executable_counter=$((executable_counter+1))

else

#Not Found

echo "'$file' is not executable"

#Incrementing Counter

nonexecutable_counter=$((nonexecutable_counter+1))

fi

# take action on each file. $f store current file name

done

#Printing the results

echo "Executable Files and Directories: '$executable_counter'"

echo "Non-Executable Files and Directories: '$nonexecutable_counter'"

**********************CODE***********************

I hope it helps. Please don't forget to thumbs up if it helped you.

Keep learning and keep HomeworkLibing.

Happy Coding :)

*************************COMPLETE*****************************