HOW MANY ML OF .1000 M SODIUM HYDROXIDE ARE REQUIRED TO TITRATE 25 ML OF .1502M OXALIC ACID
Moles of Oxalic acid = molarity×volume/1000
= 0.1502×25/1000 = 0.003755 moles
Moles of NaOH required = 2×moles of Oxalic acid
= 2×0.003755 = 0.00751 moles
Volume of NaOH = moles×1000/concentration
= 0.00751×1000/0.1000 ml = 75.1 ml
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HOW MANY ML OF .1000 M SODIUM HYDROXIDE ARE REQUIRED TO TITRATE 25 ML OF .1502M...
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