Question

A baseball outfielder throws a baseball of mass 0.24 kg at a speed of 48 m/s...

A baseball outfielder throws a baseball of mass 0.24 kg at a speed of 48 m/s and initial angle of 28 degrees. What is the kinetic energy (in J) of the baseball at the highest point of the trajectory? Ignore air friction.

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Answer #1

Solution)

Given,

Mass of baseball=0.24 kg

Initial speed=48 m/s

Angle, theta=28 degrees

Horuzintal component of velocity,

Vx=48 cos(28)

We know, at the highest point vertical velocity component=0

So,

Kinetic Energy=mVx/2=(.24 kg (48 cos(28))^2)/2=215.54 Joules (Ans)

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